[10000印刷√] f(x y)=x^2 graph 199809-F(x y)=sqrt(x^2+y^2) graph

 method 1 You can use the formula x = −b ± √b2 − 4ac 2a to determine the xintercepts Find the mid point and that is the x coordinate for the minimum Substitute back into

F(x y)=sqrt(x^2+y^2) graph-For example, take f(x)=x 2, this will give f(x2)=(x2) 2 Look at when x 2 =0 and when (x2) 2 =0 This will happen at x=0 and x=2 respectively Subsequently, the point (0,0) from (x,f(x)) has m=2 y=x^22x We can find the slope of the tangent to the curve by taking its derivative and evaluating it at the point of tangency dy/dx=2x2=2(0)2=02=2 m=2 We can

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Now let's find the x intercepts and y intercepts xintercept is the value of x when y equals 0 0 = 2 x 2 x3 0 = 2 x 2 0 = x 2 x=0 The yintercept is the value of y when x equals 0 y = 2 (0) 2 03Calculus Using the first and second derivatives, sketch the graph of f(x) = (x2)/(x1)

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